Direction for questions 1 to 5:

Based on the data in the table, answer the questions that follow. The following table presents the percentage breakup of employees and the ratio of male to female employees working in five different organisations (A to E). There is a total number of 35,000 employees working in all five organisations.

What is the difference between the number of males in Organisation D and the number of females in Organisation B?

Correct Answer: The correct answer is 1,365.

To find the difference between the number of males in Organisation D and the number of females in Organisation B, we analyze the data provided in the table:
- Total number of employees in all five organisations = 35,000
- From the table, for Organisation D: Percentage of employees is 15% and the ratio of Male to Female employees is 2:3.
- From the table, for Organisation B: Percentage of employees is 22% and the ratio of Male to Female employees is 11:9.

Step 1: Calculate the number of males in Organisation D

First, calculate the total number of employees in Organisation D:
Total employees in D = 15% of 35,000

$$\text{Total employees in D}=\frac{15}{100}\times \mathrm{35,000}=\mathrm{5,250}$$

Given the ratio of Male to Female in Organisation D is 2:3, the proportion of males is:

$$\text{Number of males in D}=\frac{2}{2+3}\times \mathrm{5,250}$$

$$=\frac{2}{5}\times \mathrm{5,250}=\mathrm{2,100}$$

Step 2: Calculate the number of females in Organisation B

First, calculate the total number of employees in Organisation B:
Total employees in B = 22% of 35,000

$$\text{Total employees in B}=\frac{22}{100}\times \mathrm{35,000}=\mathrm{7,700}$$

Given the ratio of Male to Female in Organisation B is 11:9, the proportion of females is:

$$\text{Number of females in B}=\frac{9}{11+9}\times \mathrm{7,700}$$

$$=\frac{9}{20}\times \mathrm{7,700}=\mathrm{3,465}$$

Step 3: Find the difference between the two values

$$\text{Difference}=\text{Number of females in B}-\text{Number of males in D}$$

$$=\mathrm{3,465}-\mathrm{2,100}=\mathrm{1,365}$$