Directions (31-35):The Line graph shows total number of quantities of items (P + Q) dispatched and number of quantities of item ‘Q’ dispatched out of total items of P & Q dispatched from four (A, B C & D) different warehouses in the month of march. Read the following line chart carefully and answer the questions given below.

The total number of item Q dispatched from C in February is 20% less than total number of item P dispatched from A in March. If ratio of total number of item P dispatched from C in March to February $5:4$ respectively, then find the total number of item P&Q together dispatched from C in February.

The correct answer is 320.

Step 1: Extract data from the given line graph for the month of March.

From the graph, we can observe the values for warehouses A and C in March:

For Warehouse A (March):
Total quantity of items (P + Q) dispatched = 475
Quantity of item Q dispatched = 225
Quantity of item P dispatched from A in March = 475 - 225 = 250

For Warehouse C (March):
Total quantity of items (P + Q) dispatched = 325
Quantity of item Q dispatched = 175
Quantity of item P dispatched from C in March = 325 - 175 = 150

Step 2: Calculate the number of item Q dispatched from C in February.

It is given that the total number of item Q dispatched from C in February is 20% less than the total number of item P dispatched from A in March.

$\text{Item Q from C (Feb)}=250\times (1-0.20)=250\times 0.80=200$

Step 3: Calculate the number of item P dispatched from C in February.

The ratio of total number of item P dispatched from C in March to February is $5:4$.

$\frac{\text{Item P from C (March)}}{\text{Item P from C (Feb)}}=\frac{5}{4}$

$\frac{150}{\text{Item P from C (Feb)}}=\frac{5}{4}$

$\text{Item P from C (Feb)}=\frac{150\times 4}{5}=120$

Step 4: Find the total number of items P & Q together dispatched from C in February.

$\text{Total items (P + Q) from C in Feb}=120+200=320$