Following the bar graph shows percentage distribution number of challans generated in five different cities (A,B,C,D and E) in two different months (June and July) . Total number of challans generated in June and July is 800 and 1200 respectively.

Number of challans generated in city F is 25% more than number of challans generated in city A in both the months together. Find he total number of challans generated in city F in both the months together.

The correct answer is 470.

Step 1: Understand the given data
From the problem statement, we have:
- Total number of challans generated in June = 800
- Total number of challans generated in July = 1200

From the provided bar graph, we can observe the percentage distribution of challans generated in City A:
- Percentage of challans in City A for June (blue bar) = 20%
- Percentage of challans in City A for July (orange bar) = 18%

Step 2: Calculate the number of challans generated in City A

For June:
$\text{Challans in City A (June)}=20\%\times 800=\frac{20}{100}\times 800=160$

For July:
$\text{Challans in City A (July)}=18\%\times 1200=\frac{18}{100}\times 1200=216$

Total challans generated in City A in both months together:
$\text{Total (City A)}=160+216=376$

Step 3: Calculate the total number of challans generated in City F
It is given that the number of challans in City F is 25% more than the number of challans in City A in both months together.

$\text{Total (City F)}=376\times \left(1+\frac{25}{100}\right)=376\times 1.25=470$

Thus, the total number of challans generated in City F in both months together is 470.