Question Details

For an ideal Rankine cycle operating between pressures of 30 bar and 0.04 bar, the work output from the turbine is 903 kJ/kg and the work input to the feed pump is 3 kJ/kg. The specific steam consumption is _________________ kg/kW.h (round off to 2 decimal places).

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Correct Answer :

Correct answer is : 4

WT = 903 kJ/kg, Wcomp = 3 kJ/kg

Now,

S p e c i f i c S t e a m C o n s u m p t i o n = 3600 ( W T W P )

S S C = 3600 903 3 = 3600 900 = 4

∴ SSC = 4 kg/kW.hr

Solution :

The correct answer is 4.

Step-by-step Explanation:

In an ideal Rankine cycle, the net work output per unit mass of steam circulating in the cycle, denoted as Wnet, is the difference between the work output from the turbine (WT) and the work input required by the feed pump (WP or Wcomp).
Given parameters from the problem:
Turbine work output, WT = 903 kJ/kg
Feed pump work input, WP = 3 kJ/kg

First, we calculate the net work output of the cycle per kg of steam:
Wnet = WT WP
Substituting the given values:
Wnet = 903 3 = 900 kJ/kg

Specific steam consumption (SSC) is defined as the mass flow rate of steam required to produce unit power output. It is typically expressed in kg/kW.h.
Since 1 kW.h is equal to 3600 kJ (since 1 kW = 1 kJ/s and 1 hour = 3600 seconds), we convert the power unit using this factor:
Specific Steam Consumption (SSC) = 3600 Wnet

Substituting the value of Wnet into the equation:
SSC = 3600 900 = 4 kg/kW.h
Thus, the specific steam consumption is 4 kg/kW.h.

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