Question Details

For any natural numbers $m$ , $n$ , and $k$ , such that $k$ divides both $m + 2 n$ and $3 m + 4 n$ , $k$ must be a common divisor of

Options

A

$m$ and $n$

B

$2 m$ and $3 n$

C

$2 m$ and $n$

D

$m$ and $2 n$

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