Girish scored 695 marks in an examination and was 17 marks short of 89% of the maximum marks. In the same examination, his friend scored 688 marks. What is the percentage of marks scored by his friend?

The correct option is 86%.

Let's break down the solution step-by-step to understand why this answer is correct.

Step 1: Understand the information given for Girish.
Girish scored 695 marks in the examination.
We are told that he was 17 marks short of 89% of the maximum marks.
This means that if we add 17 marks to Girish's score, he would have scored exactly 89% of the maximum marks.

$89\%\text{ of Maximum Marks}=695+17$

$89\%\text{ of Maximum Marks}=712$

Step 2: Find the maximum marks of the examination.
Let the maximum marks be M. From the equation above, we have:

$\frac{89}{100}\times M=712$

To find M, we solve the equation:

$M=\frac{712\times 100}{89}$

Dividing 712 by 89 gives exactly 8:

$M=8\times 100=800$

So, the maximum marks for the examination is 800.

Step 3: Calculate the percentage of marks scored by his friend.
His friend scored 688 marks out of the maximum of 800 marks.
To find the percentage, we use the formula:

$\text{Percentage}=\left(\frac{\text{Marks Scored}}{\text{Maximum Marks}}\right)\times 100$

Substituting the values:

$\text{Percentage}=\left(\frac{688}{800}\right)\times 100$

$\text{Percentage}=\frac{688}{8}=86\%$

Thus, Girish's friend scored 86% of the marks in the examination.