Question Details

Given below are two statements:

Statement I : All the pairs of molecules (PbO, PbO2); (SnO, SnO2) and (GeO, GeO2) contain amphoteric oxides.

Statement II : AlCl3, BH3, BeH2 and NO2 all have incomplete octet.

In the light of the above statements, choose the correct option.

Options

A

Both Statement I and Statement II are correct

B

Both Statement I and Statement II are incorrect


C

Statement I is correct but Statement II is incorrect


D

Statement I is incorrect but Statement II is correct


Show Answer

Correct Answer :

Option D

Statement I is incorrect but Statement II is correct


Statement I is incorrect but Statement II is correct

Solution :

The correct option is: Statement I is incorrect but Statement II is correct.

Let us analyze both statements step-by-step to understand why this is the correct choice:

Analysis of Statement I:
Statement I claims that all pairs of molecules (PbO, PbO2); (SnO, SnO2) and (GeO, GeO2) contain amphoteric oxides.
Let's check the nature of each oxide:

  • Lead oxides: Both PbO and PbO2 are amphoteric oxides, reacting with both acids and bases.
  • Tin oxides: Both SnO and SnO2 are amphoteric oxides, reacting with both acids and bases.
  • Germanium oxides: GeO2 is amphoteric. However, GeO (germanium(II) oxide) is classified as a distinctively acidic oxide, not amphoteric (or in some contexts, it is considered basic/acidic but not amphoteric in the standard periodic trend classifications where only the higher oxidation state oxide GeO2 shows amphoteric character while GeO is not considered amphoteric). Therefore, not all the listed pairs contain purely amphoteric oxides, making Statement I incorrect.

Analysis of Statement II:
Statement II claims that AlCl3, BH3, BeH2 and NO2 all have incomplete octet.
Let us evaluate the valence shell electron count around the central atom for each molecule:

  • AlCl3: Aluminum (Al) is in Group 13 and has 3 valence electrons. It forms three single covalent bonds with three chlorine atoms, sharing a total of 6 electrons. Thus, its valence shell has only 6 electrons, which is less than 8 (incomplete octet).
  • BH3: Boron (B) is in Group 13 and has 3 valence electrons. It forms three covalent bonds with three hydrogen atoms, sharing a total of 6 electrons. Thus, its valence shell has only 6 electrons (incomplete octet).
  • BeH2: Beryllium (Be) is in Group 2 and has 2 valence electrons. It forms two covalent bonds with two hydrogen atoms, sharing a total of 4 electrons. Thus, its valence shell has only 4 electrons (incomplete octet).
  • NO2: Nitrogen (N) is in Group 15 and has 5 valence electrons. It forms one double bond with one oxygen atom, one coordinate/single bond with another oxygen atom, and retains a single unpaired electron. The total number of valence electrons around the nitrogen atom is 7, which is an odd number and less than 8 (incomplete octet).
Since all these molecules have fewer than 8 electrons in the valence shell of their central atom, they all indeed have an incomplete octet. Therefore, Statement II is correct.

Conclusion:
Statement I is incorrect, and Statement II is correct.

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