Question Details

Identify the compound that will react with Hinsberg’s reagent to give a solid which dissolves in alkali.

Options

A

B

C

D

Show Answer

Correct Answer :

Option B

CH3-CH2-NH2

Solution :

The correct option is Option 2, which corresponds to ethylamine (CH3-CH2-NH2).

Hinsberg's Test Explanation:
Hinsberg's reagent is benzenesulfonyl chloride (C6H5SO2Cl). It is used to distinguish between primary, secondary, and tertiary amines based on their reactivity and the solubility of the resulting product in an alkali solution.

1. Reaction with Primary Amines (1° Amines):
A primary amine, such as ethylamine (CH3-CH2-NH2), reacts with benzenesulfonyl chloride to form N-ethylbenzenesulfonamide (a solid sulfonamide precipitate).
C6H5SO2Cl+CH3CH2NH2C6H5SO2NH-CH2CH3+HCl
The hydrogen atom attached to the nitrogen in this sulfonamide is strongly acidic because it is attached to a highly electronegative nitrogen atom which is adjacent to the strongly electron-withdrawing sulfonyl group (-SO2-). Due to this acidity, the sulfonamide reacts with aqueous alkali (such as NaOH or KOH) to form a soluble sodium salt, which dissolves completely to form a clear solution:
C6H5SO2NH-CH2CH3+NaOHNa+[C6H5SO2N-CH2CH3]-+H2O

2. Comparison with other classes of compounds:
• Secondary Amines (e.g., (CH3CH2)2NH) react to form an N,N-dialkylbenzenesulfonamide. Since this compound lacks any acidic hydrogen atom attached to nitrogen, it is completely insoluble in alkali.
• Tertiary Amines (e.g., (CH3CH2)3N) do not react with Hinsberg's reagent because they do not have a replaceable hydrogen atom on the nitrogen.
• Nitroethane (CH3CH2NO2) does not react with Hinsberg's reagent under these conditions.

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