Identify the correct order of organic compounds in the following chemical reaction:

(A) CH₃MgBr
(B) CH₃Br
(C) CH₃Cl
(D) CH₄

Choose the correct answer from the options given below:

The correct option is (B), (A), (C), (D).

By analyzing the chemical reaction scheme shown in the image:
$?+\mathrm{Mg}\stackrel{\text{Dry Ether}}{\to }?\stackrel{H_{2}O}{\to }?\stackrel{{\mathrm{Cl}}_2,\Delta }{\to }?$

We can identify each of the organic compounds in the sequence step-by-step:

Step 1: Preparation of Grignard Reagent
Alkyl halides react with magnesium metal ($\mathrm{Mg}$) in the presence of dry ether to yield organomagnesium halides, commonly known as Grignard reagents. In this reaction, methyl bromide, ${\mathrm{CH}}_3\mathrm{Br}$ (B), reacts with magnesium to form methylmagnesium bromide, ${\mathrm{CH}}_3\mathrm{MgBr}$ (A):
${\mathrm{CH}}_3\mathrm{Br}+\mathrm{Mg}\stackrel{\text{Dry Ether}}{\to }{\mathrm{CH}}_3\mathrm{MgBr}$
Therefore, the first reactant is (B) and the second product is (A).

Step 2: Hydrolysis of the Grignard Reagent
Grignard reagents are highly reactive bases and react instantly with proton donors such as water ($H_{2}O$). The methyl group in methylmagnesium bromide (A) takes a proton from water to produce methane, ${\mathrm{CH}}_4$ (D):
${\mathrm{CH}}_3\mathrm{MgBr}+H_{2}O\to {\mathrm{CH}}_4+\mathrm{Mg}\left(\mathrm{OH}\right)\mathrm{Br}$
Thus, the third compound in the sequence is (D).

Step 3: Chlorination of Alkane
Methane (D) undergoes free-radical halogenation when treated with chlorine gas (${\mathrm{Cl}}_2$) and heat ($\Delta$) to form methyl chloride, ${\mathrm{CH}}_3\mathrm{Cl}$ (C):
${\mathrm{CH}}_4+{\mathrm{Cl}}_2\stackrel{\Delta }{\to }{\mathrm{CH}}_3\mathrm{Cl}+\mathrm{HCl}$
Thus, the final product is (C).

Tracing the reaction sequence gives the order: (B) → (A) → (D) → (C). According to the provided options, this matches the correct option (B), (A), (C), (D).