Question Details

If x is a real number, then loge(4x-x23) is a real number if and only if

Options

A

1 ≤ x ≤2

B

-3 ≤ x ≤ 2

C

1 ≤ x ≤3

D

1 ≤x ≤ 3

Show Answer

Correct Answer :

Option C

1 ≤ x ≤3

Solution :

For the logarithmic expression loga(f(x)) to be a real number, the argument f(x) must be strictly greater than 0, and the base a must be positive and not equal to 1.

Here, the expression is log3(2x3).

Therefore, we require:
2x3>0
2x>3

Taking the logarithm to the base 2 on both sides:

1 ≤ x ≤3

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