The value of  $66÷[34-(\mathrm{32 }\text{of }2-4)÷(4\times 15\left)\right]\text{is equal to:}$

The correct answer is 2.

We need to evaluate:

$66÷[34-(32\text{of}2-4)÷(4\times 15\left)\right]$

We apply the BODMAS rule: Brackets → Of → Division → Multiplication → Addition → Subtraction. We work from the innermost brackets outward.

Step 1: Resolve "of" (multiplication)

"of" means multiplication, so:

$32\text{of}2=32\times 2=64$

Step 2: Evaluate the first bracket (32 of 2 − 4)

$(32\text{of}2-4)=64-4=60$

Step 3: Evaluate the second bracket (4 × 15)

$(4\times 15)=60$

Step 4: Perform the division inside the square bracket

$60÷60=1$

Step 5: Complete the square bracket

$34-1=33$

Step 6: Final division

$66÷33=2$

Therefore, the value of the expression is 2.