Question Details

In a test tube containing a salt, a few drops of dilute H2SO4 was added, which gave colourless vapours having the smell of vinegar. The vapours turned the blue litmus paper red. Identify the correct anion from the following:

Options

A

Acetate, CH3COO

B

Carbonate, CO32−

C

Sulphate, SO42−

D

Sulphide, S2−

Show Answer

Correct Answer :

Option A

Acetate, CH3COO

Acetate, CH₃COO⁻

Solution :

When dilute sulfuric acid (H₂SO₄) is added to a solid salt, the anion present in the salt can react with the acid to form a volatile acid.

Observation 1:
Colour‑less vapours are produced that have the characteristic smell of vinegar.

The smell of vinegar is the smell of acetic acid (CH₃COOH). Therefore the volatile acid formed must be acetic acid, which indicates that the anion in the original salt was the acetate ion (CH₃COO⁻).

Observation 2:
The vapours turn blue litmus paper red.

This confirms that the vapour is acidic, consistent with acetic acid. Other possible anions give different products:

  • Carbonate (CO₃²⁻) would produce carbon dioxide (CO₂), a colourless gas without a vinegar smell; CO₂ forms a weakly acidic solution but does not give a distinct vinegar odour.
  • Sulphate (SO₄²⁻) would not produce a volatile acidic compound; the mixture would remain largely unchanged and no characteristic odour would be observed.
  • Sulphide (S²⁻) would generate hydrogen sulphide (H₂S), which has a rotten‑egg smell, not a vinegar smell, and the gas would turn litmus black rather than red.

Since the only anion that yields a colourless, vinegar‑smelling, acidic vapour is acetate, the correct identification of the anion is:

Acetate, CH₃COO⁻

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