In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 6. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:3. Then Anjali's score exceeded Rama's score by

Let the initial scores of Rama, Mohan, and Anjali be $R$, $M$, and $A$ respectively.

According to the first condition:
$R=\frac{1}{12}(M+A)$
$\Rightarrow 12R=M+A$ — (Equation 1)

After the review, each score increases by 6. The new scores are $R+6$, $M+6$, and $A+6$ respectively. The ratio of their revised scores is:
$(A+6):(M+6):(R+6)=11:10:3$

Let the revised scores be:
$A+6=11k\Rightarrow A=11k-6$
$M+6=10k\Rightarrow M=10k-6$
$R+6=3k\Rightarrow R=3k-6$

Substitute these values into Equation 1:
$12(3k-6)=(10k-6)+(11k-6)$
$36k-72=21k-12$
$15k=60$
$k=4$

We can now find the initial scores:
$A=11\left(4\right)-6=38$
$R=3\left(4\right)-6=6$

The difference between Anjali's score and Rama's score is:
$A-R=38-6=32$