In the expression 5 * 4 * 3 * 2 * 1, * is chosen from +, –, × each at most two times. What is the smallest non-negative value of the expression?
Correct Answer :
0
Solution :
The correct option is 0.
To find the smallest non-negative value of the expression, we need to replace the four asterisks (*) in the expression:
using the operators +, -, and × such that each operator is used at most two times.
Let us choose the following operators for the placeholders:
1. First * = -
2. Second * = -
3. Third * = +
4. Fourth * = ×
This gives us the expression:
First, we verify the frequency constraint for each operator:
- The subtraction operator (-) is used 2 times.
- The addition operator (+) is used 1 time.
- The multiplication operator (×) is used 1 time.
Since every operator is used at most two times, this combination is valid.
Now, we evaluate the expression step-by-step following the standard order of operations (multiplication before addition and subtraction):
Step 1: Perform the multiplication:
Substituting this back, the expression becomes:
Step 2: Perform addition and subtraction from left to right:
- First operation:
- Second operation:
- Third operation:
Since 0 is the smallest possible non-negative number, the smallest non-negative value we can obtain is indeed 0.
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