Question Details

In triangle ABC , altitudes AD and BE are drawn to the corresponding bases. If $∠ B A C = 45 °$ and $∠ A B C = θ$ , then $\frac{A D}{B E} =$

Options

A

1

B

$\sqrt{2} \cos θ$

C

$\frac{\sin θ + \cos θ}{\sqrt{2}}$

D

$\sqrt{2} \sin θ$

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