Question Details

In which one of the following arrangements the given sequence is not strictly according to the properties indicated against it ?

Options

A

NH3 < PH3 < AsH3 < SbH3 : Increasing acidic character

B

CO2 < SiO2 < SnO2 < PbO2 : Increasing oxidizing power

C

HF < HCl < HBr < HI : Increasing acidic strength

D

H2O < H2S < H2Se < H2Te : Increasing pKa values

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Correct Answer :

Option D

H2O < H2S < H2Se < H2Te : Increasing pKa values

H2O < H2S < H2Se < H2Te : Increasing pKa values

Solution :

**Step 1: Understand what pKa measures**
pKa is defined as the negative base‑10 logarithm of the acid dissociation constant (Ka):
-log10(Ka). A lower pKa means a stronger acid (larger Ka).

**Step 2: Look up the experimental pKa values**
For the hydrides of group 16 (oxygen, sulfur, selenium, tellurium) the measured pKa values in water are approximately:
‑ H2O: pKa ≈ 15.7
‑ H2S: pKa ≈ 7.0
‑ H2Se: pKa ≈ 3.9
‑ H2Te: pKa ≈ 2.6

**Step 3: Arrange the compounds in order of increasing pKa**
Since pKa increases from a lower value to a higher value, the correct ascending sequence is:
H2Te (2.6) < H2Se (3.9) < H2S (7.0) < H2O (15.7).

**Step 4: Compare with the given arrangement**
The statement in the option lists the series as:
H2O < H2S < H2Se < H2Te.

**Step 5: Identify the inconsistency**
In this sequence, the pKa values are actually decreasing (15.7 → 7.0 → 3.9 → 2.6), which corresponds to **increasing acidity**, not increasing pKa. Therefore the arrangement does **not** follow the property “Increasing pKa values”.

**Conclusion**
The option “H2O < H2S < H2Se < H2Te : Increasing pKa values” is the one where the given sequence is not strictly according to the indicated property.

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