Mindyard | Let a 1 , a 2 , ... , a 52 be positive integers such that a 1 < a 2 < ... < a 52 . Suppose, their arithmetic mean is one less than the arithmetic mean of a 2 , a 3 , ..., a 52 . If a 52 = 100, then the largest possible value of a 1 is 20, 23, 48, 45

Let a₁, a₂, ... , a₅₂ be positive integers such that a₁ < a₂ < ... < a₅₂. Suppose, their arithmetic mean is one less than the arithmetic mean of a₂, a₃, ..., a₅₂. If a₅₂ = 100, then the largest possible value of a₁ is

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Let a₁, a₂, ... , a₅₂ be positive integers such that a₁ < a₂ < ... < a₅₂. Suppose, their arithmetic mean is one less than the arithmetic mean of a₂, a₃, ..., a₅₂. If a₅₂ = 100, then the largest possible value of a₁ is

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Let a1, a2, ... , a52 be positive integers such that a1 < a2 < ... < a52. Suppose, their arithmetic mean is one less than the arithmetic mean of a2, a3, ..., a52. If a52 = 100, then the largest possible value of a1 is

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Get 3 Months FREE trial

You may also like

Study Material

CTET Paper 2 Set E 20th Aug 2023 Question Paper with Solutions

CTET Paper 2 Set M 31st Jan 2021 Question Paper with Solutions

Mock Tests

CTET Paper 2 Set E 20th Aug 2023

CTET Paper 2 Set M 31st Jan 2021

Ask AI Tutor

Let a₁, a₂, ... , a₅₂ be positive integers such that a₁ < a₂ < ... < a₅₂. Suppose, their arithmetic mean is one less than the arithmetic mean of a₂, a₃, ..., a₅₂. If a₅₂ = 100, then the largest possible value of a₁ is