LIST-I contains compounds and LIST-II contains reactions
| List-I | List-II |
|---|---|
| (I) H2O2 | (P) Mg(HCO3)2 + Ca(OH)2 |
| (II) Mg(OH)2 | (Q) BaO2 + H2SO4 |
| (III) BaCl2 | (R) Ca(OH)2 + MgCl2 |
| (IV) CaCO3 | (S) BaO2 + HCl |
| (T) Ca(HCO3)2 + Ca(OH)2 |
Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option
Correct Answer :
I → Q; II → R; III → S; IV → P
Solution :
Correct Answer: I → Q; II → R; III → S; IV → P
To match each compound in LIST-I with its appropriate formation reaction in LIST-II, let us analyze each chemical reaction provided:
1. Preparation of H2O2 (Hydrogen Peroxide):
Hydrated barium peroxide (BaO2·8H2O) reacts with acidified sulfuric acid (H2SO4) to yield hydrogen peroxide along with a precipitate of barium sulfate:
BaO2 + H2SO4 → BaSO4 + H2O2
Therefore, (I) H2O2 matches with reaction (Q).
2. Preparation of Mg(OH)2 (Magnesium Hydroxide):
When calcium hydroxide reacts with magnesium chloride, magnesium hydroxide precipitates out along with calcium chloride:
Ca(OH)2 + MgCl2 → Mg(OH)2 + CaCl2
Therefore, (II) Mg(OH)2 matches with reaction (R).
3. Preparation of BaCl2 (Barium Chloride):
Barium peroxide reacts with hydrochloric acid to produce barium chloride and hydrogen peroxide:
BaO2 + 2HCl → BaCl2 + H2O2
Therefore, (III) BaCl2 matches with reaction (S).
4. Preparation of CaCO3 (Calcium Carbonate):
In Clark's process / water softening reactions, calcium hydroxide reacts with magnesium bicarbonate to precipitate calcium carbonate along with magnesium hydroxide and water:
Mg(HCO3)2 + 2Ca(OH)2 → 2CaCO3 + Mg(OH)2 + 2H2O
Therefore, (IV) CaCO3 matches with reaction (P).
Matching Summary:
(I) → (Q)
(II) → (R)
(III) → (S)
(IV) → (P)
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