Match List - I with List - II and choose the correct answer.

The correct option is (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i).

Let us analyze each chemical reaction shown in List - I and match it with its corresponding name in List - II based on the provided image:

(a) Conversion of Benzene to Benzaldehyde:

In reaction (a), Benzene reacts with carbon monoxide ($\text{CO}$) and hydrogen chloride ($\text{HCl}$) in the presence of anhydrous aluminium chloride (${\text{AlCl}}_3$) and cuprous chloride ($\text{CuCl}$). This is the standard Gattermann-Koch reaction used to synthesize benzaldehyde.

Therefore, (a) matches with (ii).

(b) Reaction of Methyl Ketones with Sodium Hypohalite:

In reaction (b), a methyl ketone ($\text{R-C(=O)-}{\text{CH}}_3$) is treated with sodium hypohalite ($\text{NaOX}$). This is the characteristic Haloform reaction, which oxidizes methyl ketones into carboxylate salts and forms haloform (${\text{CHX}}_3$).

Therefore, (b) matches with (iii).

(c) Reaction of Alcohol with Carboxylic Acid:

In reaction (c), a primary alcohol ($\text{R-}{\text{CH}}_2\text{-OH}$) reacts with a carboxylic acid ($\text{R'COOH}$) in the presence of concentrated sulfuric acid (${\text{Conc. H}}_2{\text{SO}}_4$). This dehydration condensation reaction yields an ester and water, known as Esterification.

Therefore, (c) matches with (iv).

(d) Halogenation of Aliphatic Carboxylic Acids:

In reaction (d), a carboxylic acid containing an α-hydrogen ($\text{R-}{\text{CH}}_2\text{COOH}$) is treated with halogen (${\text{X}}_2$) in the presence of red phosphorus ($\text{Red P}$), followed by hydrolysis with ${\text{H}}_2\text{O}$. This reaction selectively halogenates the α-position and is known as the Hell-Volhard-Zelinsky (HVZ) reaction.

Therefore, (d) matches with (i).

Combining all the correct matches gives:

(a) → (ii)
(b) → (iii)
(c) → (iv)
(d) → (i)

Thus, the correct option matching List - I with List - II is (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i).