Match List-I with List-II:

$\begin{array}{|clcl|}\hline & \text{List-I}& & \text{List-II}\\ \text{(A)}& \text{Urease}& \text{(I)}& \text{Maltose}\\ \text{(B)}& \text{Maltase}& \text{(II)}& \text{Glucose and fructose}\\ \text{(C)}& \text{Invertase}& \text{(III)}& {\mathrm{NH}}_3\text{and}{\mathrm{CO}}_2\\ \text{(D)}& \text{Diastase}& \text{(IV)}& \text{Glucose}\\ \hline\end{array}$

Choose the correct answer from the options given below:

The correct answer is (A)-(III), (B)-(IV), (C)-(II), (D)-(I).

To understand why this match is correct, let us analyze the functions and substrates of each enzyme listed in List-I:

(A) Urease matches with (III) NH₃ and CO₂:
Urease is an enzyme that catalyzes the hydrolysis of urea into ammonia (NH₃) and carbon dioxide (CO₂). The chemical reaction is represented as follows:
${\left({\mathrm{NH}}_2\right)}_2\mathrm{CO}+H_{2}O\to 2{\mathrm{NH}}_3+{\mathrm{CO}}_2$

(B) Maltase matches with (IV) Glucose:
Maltase is an enzyme present in saliva and pancreatic juice that catalyzes the breakdown of maltose (a disaccharide) into two molecules of the simple sugar glucose (a monosaccharide).

(C) Invertase matches with (II) Glucose and fructose:
Invertase (also known as sucrase) catalyzes the hydrolysis of sucrose (cane sugar) into its constituent monosaccharides, which are glucose and fructose. The resulting mixture of glucose and fructose is often called invert sugar.

(D) Diastase matches with (I) Maltose:
Diastase is an enzyme group (specifically amylases) that catalyzes the breakdown of starch into maltose. Therefore, the product associated with diastase action in this context is maltose.

By combining these matches, we get:
• (A) - (III)
• (B) - (IV)
• (C) - (II)
• (D) - (I)