Match List-I with List-II

List-I	List-II
Concepts	Related Terms
(A) Ambident nucleophiles	(I) Symmetrical object
(B) Plane polarized light	(II) Saytzeff rule
(C) Superimposable mirror image	(III) Cyanides and nitrites
(D) β-elimination reaction	(IV) Nicol Prism

Choose the correct answer from the options given below

The correct option is (A) – (III), (B) – (IV), (C) – (I), (D) – (II).

Let us analyze and match each concept in List-I with its corresponding term in List-II step-by-step:

(A) Ambident nucleophiles matches with (III) Cyanides and nitrites:
Ambident nucleophiles are species that possess two nucleophilic centers (or donor atoms) through either of which they can attack a substrate. For example, the cyanide ion (${\mathrm{CN}}^{-}$) can act as a nucleophile either through the carbon atom to form cyanides (alkyl nitriles) or through the nitrogen atom to form isocyanides. Similarly, nitrite ion (${\mathrm{NO}}_2^{-}$) can link via the nitrogen atom to form nitroalkanes or via the oxygen atom to form alkyl nitrites. Thus, (A) matches with (III).

(B) Plane polarized light matches with (IV) Nicol Prism:
Ordinary light consists of electromagnetic waves vibrating in all possible planes perpendicular to the direction of propagation. When ordinary light is passed through a Nicol prism (made of calcite crystal), it filters out the vibrations in all directions except one. The resulting light, which vibrates in only one plane, is known as plane-polarized light. Therefore, a Nicol prism is used to produce plane-polarized light, so (B) matches with (IV).

(C) Superimposable mirror image matches with (I) Symmetrical object:
An object that possesses a plane of symmetry or center of symmetry is achiral, meaning its mirror image is identical to and can be perfectly superimposed on the original object. Therefore, a symmetrical object is characterised by having a superimposable mirror image. Thus, (C) matches with (I).

(D) β-elimination reaction matches with (II) Saytzeff rule:
In a β-elimination (dehydrohalogenation) reaction, a hydrogen atom from the β-carbon and a halogen atom from the α-carbon are eliminated to form an alkene. When more than one β-carbon containing hydrogen is present, multiple alkenes can form. The Saytzeff (or Zaitsev) rule states that in such elimination reactions, the preferred product is the highly substituted alkene (the alkene containing a greater number of alkyl groups attached to the doubly bonded carbon atoms). Thus, (D) matches with (II).

Combining all the individual matches, we get:
(A) – (III), (B) – (IV), (C) – (I), (D) – (II).