Match List-I with List-II

List-I	List-II
Property	Unit
(A) Cell constant	(I) cm⁻¹
(B) Molar conductance	(II) ohm⁻¹ cm² mol⁻¹
(C) Specific conductance	(III) ohm⁻¹ cm⁻¹
(D) Conductance	(IV) ohm⁻¹

Choose the correct answer from the options given below:

The correct option is (A) – (I), (B) – (II), (C) – (III), (D) – (IV).

Let us verify the units for each electrochemical property step-by-step:

(A) Cell constant:
The cell constant ($G*$) of a conductivity cell is defined as the ratio of the distance between the electrodes ($l$) to their cross-sectional area ($A$):

$G^{*}=\frac{l}{A}$

In CGS units, distance is measured in centimeters ($\mathrm{cm}$) and area in square centimeters (${\mathrm{cm}}^2$). Therefore, the unit is:

$\frac{\mathrm{cm}}{{\mathrm{cm}}^2}={\mathrm{cm}}^{\&\#x2212;1}$

This matches (A) – (I).

(B) Molar conductance:
Molar conductance (${\mathrm{\&\#x039B;}}_m$) is related to electrolytic conductivity or specific conductance ($\mathrm{\&\#x03BA;}$) and molarity concentration ($C$) by the formula:

${\mathrm{\&\#x039B;}}_m=\frac{\mathrm{\&\#x03BA;}}{C}$

Using specific conductance in ${\mathrm{ohm}}^{\&\#x2212;1}{\mathrm{cm}}^{\&\#x2212;1}$ and concentration in $\mathrm{mol}{\mathrm{cm}}^{\&\#x2212;3}$, the unit for molar conductance becomes:

$\frac{{\mathrm{ohm}}^{\&\#x2212;1}{\mathrm{cm}}^{\&\#x2212;1}}{\mathrm{mol}{\mathrm{cm}}^{\&\#x2212;3}}={\mathrm{ohm}}^{\&\#x2212;1}{\mathrm{cm}}^2{\mathrm{mol}}^{\&\#x2212;1}$

This matches (B) – (II).

(C) Specific conductance:
Specific conductance or conductivity ($\mathrm{\&\#x03BA;}$) is the reciprocal of resistivity ($\mathrm{\&\#x03C1;}$):

$\mathrm{\&\#x03BA;}=\frac{1}{\mathrm{\&\#x03C1;}}=\frac{1}{R}\&\#x00D7;\frac{l}{A}$

Since resistance $R$ is measured in ohms ($\mathrm{\&\#x03A9;}$) and the cell constant $\frac{l}{A}$ in ${\mathrm{cm}}^{\&\#x2212;1}$, the unit is:

${\mathrm{ohm}}^{\&\#x2212;1}{\mathrm{cm}}^{\&\#x2212;1}$

This matches (C) – (III).

(D) Conductance:
Conductance ($G$) is the reciprocal of electrical resistance ($R$):

$G=\frac{1}{R}$

Since the unit of resistance is ohm, the unit of conductance is:

${\mathrm{ohm}}^{\&\#x2212;1}$

This matches (D) – (IV).