| List-I (Mixture) | List-II (Method of separation) | |
|---|---|---|
| A. | + | (I) Distillation under reduced pressure |
| B. | Crude oil in petroleum industry | (II) Steam distillation |
| C. | Glycerol from spent-lye | (III) Fractional distillation |
| D. | Aniline - water | (IV) Simple distillation |
Correct Answer :
A-III, B-IV, C-I, D-II
Solution :
We have to match each mixture in List‑I with the most suitable method of separation in List‑II.
Mixture A: CHCl₃ + C₆H₅NH₂ (chloroform + aniline)
The two components are both organic liquids but their boiling points differ markedly: chloroform boils at ≈ 61 °C, whereas aniline boils at ≈ 184 °C. When the difference is large, a simple distillation would waste a lot of energy, while fractional distillation can efficiently separate a low‑boiling component from a high‑boiling one by using a column that provides many theoretical plates. Hence the appropriate method is **Fractional distillation (III)**.
Mixture B: Crude oil in the petroleum industry
Crude oil consists of a very wide range of hydrocarbons with large differences in boiling points (from ≈ 30 °C up to ≈ 600 °C). When the boiling points are far apart, a **Simple distillation (IV)** is sufficient to collect the lighter fractions without the need for a long fractionating column. Therefore, crude oil is initially separated by simple distillation.
Mixture C: Glycerol from spent‑lye
This mixture is mainly water (boiling ≈ 100 °C) and glycerol (boiling ≈ 290 °C). Direct heating would decompose glycerol, so the technique used is **Steam distillation (I)**: steam carries over the low‑boiling water while glycerol remains in the residue, allowing its recovery without high temperatures.
Mixture D: Aniline + water
Aniline has a boiling point of ≈ 184 °C, far above that of water. To separate it from water without heating aniline to its high boiling point, **Steam distillation (II)** is employed. The water‑steam mixture vaporizes at 100 °C, dragging a small amount of aniline into the vapor phase, which is then condensed and collected.
Thus the correct matching is:
A��→ III, B → IV, C → I, D → II.
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