Match List I with List II

List-I (Reaction)		List-II (Reagents/Condition)
(A)		(I)
(B)		(II)	$Cr{O}_3$
(C)		(III)	$KMn{O}_4/KOH,\mathrm{\Delta \; <!--\; \Delta \; -->}$
(D)		(IV)	(i) $O_3$ (ii) $Zn-\; <!--\; -\; -->H_{2}O$

Choose the correct answer from the options given below:

The correct option is A-IV, B-I, C-II, D-III.

Let's analyze the reactions in List-I and match them with the reagents/conditions in List-II step-by-step:

1. Reaction (A):
The reactant shown in the image is bicyclohexylidene (two cyclohexyl rings connected by a double bond), which is cleaved and converted into two molecules of cyclohexanone:
$C_{12}{H}_{20}\to 2C_6{H}_{10}O$
This is an oxidative cleavage of an alkene across its double bond to form carbonyl compounds. The appropriate reagent for this conversion is reductive ozonolysis, which corresponds to (IV):
${\text{(i) O}}_3{\text{(ii) Zn - H}}_2\text{O}$
Thus, A matches with IV.

2. Reaction (B):
The reactant shown in the image is benzene, which is converted to benzophenone:
$C_6{H}_6\to C_6{H}_5{\text{COC}}_6{H}_5$
This is a Friedel-Crafts acylation reaction. Benzene reacts with benzoyl chloride in the presence of a Lewis acid catalyst (anhydrous aluminium chloride) to form benzophenone. The reagent shown in the image for (I) is benzoyl chloride and anhydrous aluminium chloride:
$C_6{H}_5{\text{COCl / Anhydrous AlCl}}_3$
Thus, B matches with I.

3. Reaction (C):
The reactant shown in the image is cyclohexanol, which is oxidized to cyclohexanone (a ketone):
$C_6{H}_{11}\text{OH}\to C_6{H}_{10}\text{O}$
This represents the oxidation of a secondary alcohol to a ketone. The reagent used for this oxidation is chromium trioxide, which corresponds to (II):
${\text{CrO}}_3$
Thus, C matches with II.

4. Reaction (D):
The reactant shown in the image is ethylbenzene, which is converted to potassium benzoate:
$C_6{H}_5{\text{CH}}_2{\text{CH}}_3\to C_6{H}_5\text{COOK}$
This is the oxidation of the alkyl side chain of an aromatic ring to a carboxylic acid salt. The reagent used for this strong oxidation is alkaline potassium permanganate with heating, which corresponds to (III):
${\text{KMnO}}_4\text{/ KOH,}\Delta$
Thus, D matches with III.

Combining all the correct matches, we obtain:
A-IV, B-I, C-II, D-III