Question Details

Match the compounds in List-I with the appropriate observations in List-II and choose the correct option.

Options

P → 1; Q → 5; R → 4; S → 2

P → 2; Q → 5; R → 1; S → 3

P → 5; Q → 2; R → 1; S → 4

P → 2; Q → 1; R → 5; S → 3

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Correct Answer :

Option B

P → 2; Q → 5; R → 1; S → 3

Solution :

Correct Answer: P → 2; Q → 5; R → 1; S → 3

Let us analyze the chemical properties and qualitative tests for each compound given in List-I to match them with the appropriate observations in List-II:

1. Analysis of Compound (P):

Compound (P) contains a free primary aliphatic amino group (-NH₂) and a phenolic hydroxyl group (-OH) attached to a benzene ring (a tyrosine derivative component).
- Due to the presence of the free primary amino group (-NH₂), it reacts positively with ninhydrin to produce a purple color (Ruhemann's purple).
- Due to the presence of the phenolic -OH group, it reacts with neutral FeCl₃ to give a characteristic violet color complex.
Therefore, P matches with (2).

2. Analysis of Compound (Q):

Compound (Q) has an acetylated amino group at the N-terminus, so it lacks a free primary amino group and initially gives a negative ninhydrin test.
- Upon complete hydrolysis of the peptide and ester bonds, free amino acids with free primary amino groups are released, which then give a positive ninhydrin test.
- Since it contains a phenyl ring without a phenolic -OH group (unlike tyrosine), it does not give a positive phthalein dye test.
Therefore, Q matches with (5).

3. Analysis of Compound (R):

Compound (R) is anilinium chloride (C₆H₅NH₃⁺Cl^-), which dissociates in solution to provide free aniline (C₆H₅NH₂).
- Aniline acts as a nucleophile when treated with a phenyl diazonium salt (coupling reaction) under weakly acidic/neutral conditions to form an azobenzene derivative, producing a characteristic yellow dye.
Therefore, R matches with (1).

4. Analysis of Compound (S):

Compound (S) is 2,4,6-trimethylphenylhydrazine (a derivative of phenylhydrazine containing a free -NHNH₂ group).
- Substituted hydrazines react with carbonyl compounds such as glucose to form the corresponding hydrazone (or osazone).
Therefore, S matches with (3).

Conclusion:

The correct matching sequence is: P → 2; Q → 5; R → 1; S → 3.