Question Details

Match the compounds in LIST-I with the observations in LIST-II, and choose the correct option.

List-I List-II
(I) Aniline (P) Sodium fusion extract of the compound on boiling with FeSO4, followed by acidification with conc. H2SO4, gives Prussian blue color.
(II) o-Cresol (Q) Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
(III) Cysteine (R) Addition of the compound to a saturated solution of NaHCO3 results in effervescence.
(IV) Caprolactam (S) The compound reacts with bromine water to give a white precipitate.
(T) Treating the compound with neutral FeCl3 solution produces violet color.

Options

A

I → P, Q; II → S; III → Q, R; IV → P

B

I → P; II → R, S; III → R; IV → Q, S

C

I → Q, S; II → P, T; III → P; IV → S

D

I → P, S; II → T; III → Q, R; IV → P

Show Answer

Correct Answer :

Option D

I → P, S; II → T; III → Q, R; IV → P

Solution :

Correct Option: I → P, S; II → T; III → Q, R; IV → P


To match each compound in LIST-I with its correct qualitative test observation in LIST-II, let us analyze the functional groups and elements present in each compound step-by-step:


1. Compound (I): Aniline

Aniline is an aromatic primary amine containing Nitrogen (N) bound to a benzene ring.

Lassaigne's Test for Nitrogen (P): Aniline contains nitrogen. In Lassaigne's sodium fusion test, nitrogen reacts with sodium and carbon to form sodium cyanide (NaCN). When boiled with ferrous sulfate (FeSO4) and acidified with concentrated H2SO4, it forms Prussian blue precipitate [Fe4[Fe(CN)6]3]. Hence, Aniline matches with (P).

Bromine Water Test (S): Due to the strong activating nature of the -NH2 group on the benzene ring, aniline undergoes rapid electrophilic aromatic substitution with bromine water to form a white precipitate of 2,4,6-tribromoaniline. Hence, Aniline also matches with (S).

Thus, I → P, S.


2. Compound (II): o-Cresol

o-Cresol is a phenolic compound containing a phenolic -OH group attached to the aromatic ring.

Neutral FeCl3 Test (T): Phenols react with neutral ferric chloride (FeCl3) solution to form a characteristic violet-colored complex [Fe(OC6H4CH3)6]3-. Hence, o-Cresol matches with (T).

Thus, II → T.


3. Compound (III): Cysteine

Cysteine is an amino acid with the formula HS-CH2-CH(NH2)-COOH containing both Nitrogen (N) and Sulfur (S) as well as a carboxylic acid (-COOH) group.

Lassaigne's Test for N and S present together (Q): When both nitrogen and sulfur are present in an organic compound, sodium fusion converts them into sodium thiocyanate (NaSCN). Upon treatment with ferric ions or sodium nitroprusside in specific acidic/alkaline conditions, it gives a characteristic blood-red coloration [Fe(SCN)]2+. Hence, Cysteine matches with (Q).

NaHCO3 Effervescence Test (R): Cysteine contains a carboxylic acid group (-COOH), which reacts with saturated sodium bicarbonate (NaHCO3) solution to release carbon dioxide gas (CO2), producing brisk effervescence. Hence, Cysteine also matches with (R).

Thus, III → Q, R.


4. Compound (IV): Caprolactam

Caprolactam is a cyclic amide containing Nitrogen (N) in its ring structure.

Lassaigne's Test for Nitrogen (P): Since it contains nitrogen, its sodium fusion extract forms NaCN, which yields a Prussian blue color upon boiling with FeSO4 followed by acidification with concentrated H2SO4. Hence, Caprolactam matches with (P).

Thus, IV → P.


Combining all the correct matches gives:

I → P, S; II → T; III → Q, R; IV → P

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