Question Details

O and C are respectively the orthocentre and the circumcentre of an acute angled triangle PQR. QCR=138°. A perpendicular PM is dropped from P on side QR. If PQR=52°, what is the degree measure of RPM?

Options

A

38

B

42

C

69

D

31

Show Answer

Correct Answer :

Option D

31

Solution :

` tags, matching the format constraints.

The correct option is 31.

Here is the step-by-step logical explanation and mathematical derivation:

Step 1: Relate the circumcentre angle to the vertex angle.
We are given that C is the circumcentre of the acute-angled triangle PQR, and the angle at the circumcentre is:
QCR=138°

According to the circumcentre theorem, the angle subtended by an arc at the centre of a circle is twice the angle subtended by it at any point on the remaining part of the circle. Therefore, the angle at vertex P is half of the circumcentre angle:
QPR=12QCR

Substituting the given value:
QPR=138°2=69°

Step 2: Find the third angle of triangle PQR.
We are given that PQR=52°.
Using the angle sum property of a triangle for PQR, we have:
QPR+PQR+PRQ=180°

Substituting the known values:
69°+52°+PRQ=180°

Simplifying the equation:
121°+PRQ=180°
PRQ=180°-121°=59°

Step 3: Calculate the measure of angle RPM.
A perpendicular PM is dropped from vertex P onto the side QR. This creates a right-angled triangle PMR at point M, which means:
PMR=90°

In the right-angled triangle PMR, the sum of the interior angles is also 180°:
RPM+PMR+PRM=180°

Note that PRM is the same angle as PRQ which is 59°. Substituting the values:
RPM+90°+59°=180°

Simplifying the equation:
RPM+149°=180°
RPM=180°-149°=31°

Thus, the degree measure of RPM is indeed 31.

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