Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest. Find the value of the smallest angle.

The correct answer is 30°.

Step-by-step explanation:

Let the measure of the smallest angle of the triangle be $x$.

According to the given problem statement, the remaining two angles are twice and thrice the smallest angle respectively:

Second angle = $2x$
Third angle = $3x$

We know that the sum of the interior angles of any triangle is always equal to 180°.

$x+2x+3x=180°$

Combining the like terms on the left side of the equation:

$6x=180°$

Now, divide both sides by 6 to solve for $x$:

$x=\frac{180°}{6}$

$x=30°$

Thus, the value of the smallest angle is 30°.