On account of corona virus, 5% of the population of a village died. Out of the remaining population, 20% fled due to panic. If the present population is 4655, then what was the population of the village before the corona attack?

The correct option is 6125.

Let us solve this step-by-step to find the original population of the village before the coronavirus outbreak.

Step 1: Define the original population
Let the initial population of the village before the corona attack be $P$.

Step 2: Account for the deaths due to coronavirus
It is given that 5% of the population died. Therefore, the percentage of the remaining population is:

$100\%-5\%=95\%$

So, the population remaining after the deaths is:

$0.95\×P$

Step 3: Account for the people who fled due to panic
Out of the remaining population, 20% fled. This means that 80% of the remaining population stayed in the village:

$100\%-20\%=80\%$

Therefore, the present population is 80% of the remaining 95% of $P$:

$\text{Present Population}=80\%\×(95\%\×P)$

$\text{Present Population}=\frac{80}{100}\×\frac{95}{100}\×P$

$\text{Present Population}=\frac{4}{5}\×\frac{19}{20}\×P$

$\text{Present Population}=\frac{76}{100}\×P=0.76P$

Step 4: Solve for the original population ($P$)
We are given that the present population is 4655. Setting up the equation:

$0.76P=4655$

$P=\frac{4655}{0.76}$

$P=\frac{4655\×100}{76}$

Dividing 4655 by 76:

$4655\÷76=61.25$

$P=61.25\×100=6125$

Thus, the population of the village before the corona attack was 6125.