Question Details

P is a point on line AB and PQ is a ray such that QPA=7x and QPB=5x. Then, the value of (8x − 10°) is :

Options

A

118°

B

110°

C

140°

D

102°

Show Answer

Correct Answer :

Option B

110°

Solution :

The correct answer is 110°.

Step-by-step Explanation:

1. Since P is a point on the straight line AB and ray PQ stands on it, the angles QPA and QPB form a linear pair.

2. The sum of angles forming a linear pair on a straight line is equal to 180°:

QPA+QPB=180°

3. Substitute the given values QPA=7x and QPB=5x into the equation:

7x+5x=180°

12x=180°

x=180°12

x=15°

4. Now, calculate the value of (8x-10°) by substituting x=15°:

8x-10°=8(15°)-10°

8x-10°=120°-10°=110°

Thus, the value of (8x-10°) is 110°.

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