Pie chart given below shows the percentage distribution of marks obtained in maths out of total marks obtained by five students (i.e., A, B, C, D and E) of a class in math. There are only three subjects in class i.e. (Hindi, English and Math) .

When the combined Mathematics score of these five students is 600, by how many marks does B's Mathematics score exceed A's?

The correct answer is 48.

From the given pie chart, we can observe the percentage distribution of marks obtained in Mathematics by five students (A, B, C, D, and E):

• Student A (Red sector): 12.5%
• Student B (Yellow sector): 20.5% (or calculated via total sum 100% - (12.5% + 14% + 18% + 15%) = 20.5%)
• Student C (Grey sector): 14%
• Student D (Green sector): 18%
• Student E (Blue sector): 15%

We are given that the total combined Mathematics score of all five students is 600.

Step 1: Calculate the percentage difference between B's score and A's score

Percentage difference = Percentage share of B - Percentage share of A

$\text{Percentage difference}=20.5\%-12.5\%=8\%$

Step 2: Calculate by how many marks B's score exceeds A's score

Difference in marks = 8% of Total Mathematics Score (600)

$\text{Difference in marks}=\frac{8}{100}\×600$

$\text{Difference in marks}=8\×6=48$

Thus, B's Mathematics score exceeds A's Mathematics score by 48 marks.