Question Details

Quantity I. A's salary is 40% of B's salary & B's salary 25% of C's salary. What percentage of C's salary is A's salary? Quantity Il. Two numbers are less than a third number by 30% and 37% respectively. How much percent is the second number less than the first?

Options

A

Quantity I > Quantity Il

B

Quantity | < Quantity Il

C

Quantity | = Quantity ll or no relation cannot be established

D

Quantity I ≥ Quantity lI

E

Quantity | ≤ Quantity Il

Show Answer

Correct Answer :

Option C

Quantity | = Quantity ll or no relation cannot be established

Solution :

To find the correct relationship between the two quantities, we will calculate the value of each quantity step-by-step.

Step 1: Calculate Quantity I
Let A's salary, B's salary, and C's salary be represented by A, B, and C respectively.
According to the question, A's salary is 40% of B's salary:
A=40100×B=0.4B
And B's salary is 25% of C's salary:
B=25100×C=0.25C

Now, substitute the value of B in the equation for A:
A=0.4×(0.25C)
A=0.1C

To express A's salary as a percentage of C's salary:
Percentage=AC×100%=0.1CC×100%=10%
Thus, Quantity I = 10%.

Step 2: Calculate Quantity II
Let the third number be 100.
The first number is 30% less than the third number:
First Number=100-30=70
The second number is 37% less than the third number:
Second Number=100-37=63

Now, we find how much percent the second number is less than the first number:
Difference=70-63=7
Percentage Less=DifferenceFirst Number×100%
Percentage Less=770×100%=10%
Thus, Quantity II = 10%.

Conclusion:
Comparing the two values:
Quantity I = 10%
Quantity II = 10%
Therefore, Quantity I = Quantity II.

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