Read the following information carefully and answer the questions given below. The information about three sellers who sold two types of rice, i.e., brown and white.

The quantity of white rice sold by all three seller is 230 kg. The quantity of brown rice sold by B is 20% more than the quantity of white rice sold by A. The quantity of white rice sold by B is 20 kg more than that of brown rice. The ratio of brown rice sold by A to B is 2:3. The average quantity of brown rice sold by all three sellers is 60 kg, and the total rice (white and brown) sold by C is 75 kg.

The total quantity of white rice sold by C is how much more or less than the total quantity of brown rice sold by A (in Kg).

To find the total quantity of white rice sold by C and compare it to the brown rice sold by A, we can set up algebraic equations using the given information.

Let the quantities of rice sold by sellers A, B, and C be represented as follows:
- Brown rice sold by A, B, and C: $A_{\text{brown}}$, $B_{\text{brown}}$, and $C_{\text{brown}}$ respectively.
- White rice sold by A, B, and C: $A_{\text{white}}$, $B_{\text{white}}$, and $C_{\text{white}}$ respectively.

We are given the following conditions:

1. The total quantity of white rice sold by all three sellers is 230 kg:
$A_{\text{white}}+B_{\text{white}}+C_{\text{white}}=230$

2. The quantity of brown rice sold by B is 20% more than the white rice sold by A:
$B_{\text{brown}}=1.2\times A_{\text{white}}$

3. The quantity of white rice sold by B is 20 kg more than B's brown rice:
$B_{\text{white}}=B_{\text{brown}}+20$

4. The ratio of brown rice sold by A to B is 2:3:
$\frac{A_{\text{brown}}}{B_{\text{brown}}}=\frac{2}{3}\Rightarrow A_{\text{brown}}=\frac{2}{3}{B}_{\text{brown}}$

5. The average quantity of brown rice sold by all three sellers is 60 kg:
$\frac{A_{\text{brown}}+B_{\text{brown}}+C_{\text{brown}}}{3}=60\Rightarrow A_{\text{brown}}+B_{\text{brown}}+C_{\text{brown}}=180$

6. The total rice (white + brown) sold by C is 75 kg:
$C_{\text{white}}+C_{\text{brown}}=75$

Now, let us express all variables in terms of $A_{\text{white}}$ to solve the equations:

From condition 2:
$B_{\text{brown}}=1.2A_{\text{white}}$

From condition 3:
$B_{\text{white}}=1.2A_{\text{white}}+20$

From condition 4:
$A_{\text{brown}}=\frac{2}{3}\left(1.2A_{\text{white}}\right)=0.8A_{\text{white}}$

Using condition 6, we express $C_{\text{brown}}$ as:
$C_{\text{brown}}=75-C_{\text{white}}$

Substitute this into the brown rice sum equation (condition 5):
$A_{\text{brown}}+B_{\text{brown}}+(75-C_{\text{white}})=180$
$A_{\text{brown}}+B_{\text{brown}}-C_{\text{white}}=105$

From condition 1, we can write:
$C_{\text{white}}=230-A_{\text{white}}-B_{\text{white}}$

Now, substitute the expression for $C_{\text{white}}$ into our brown rice equation:
$A_{\text{brown}}+B_{\text{brown}}-(230-A_{\text{white}}-B_{\text{white}})=105$
$A_{\text{brown}}+B_{\text{brown}}+A_{\text{white}}+B_{\text{white}}=335$

Substitute our representations in terms of $A_{\text{white}}$:
$0.8A_{\text{white}}+1.2A_{\text{white}}+A_{\text{white}}+1.2A_{\text{white}}+20=335$
$4.2A_{\text{white}}+20=335$
$4.2A_{\text{white}}=315$
$A_{\text{white}}=\frac{315}{4.2}=75\text{kg}$

Now, let's calculate the required values:
- Total quantity of brown rice sold by A ($A_{\text{brown}}$):
$A_{\text{brown}}=0.8\times 75=60\text{kg}$

- Total quantity of white rice sold by B ($B_{\text{white}}$):
$B_{\text{white}}=1.2\times 75+20=110\text{kg}$

- Total quantity of white rice sold by C ($C_{\text{white}}$):
$C_{\text{white}}=230-A_{\text{white}}-B_{\text{white}}$
$C_{\text{white}}=230-75-110=45\text{kg}$

Finally, we find the difference between the total white rice sold by C and the brown rice sold by A:
$\text{Difference}=A_{\text{brown}}-C_{\text{white}}$
$\text{Difference}=60-45=15\text{kg}$

Therefore, the total quantity of white rice sold by C is 15 kg less than the total quantity of brown rice sold by A.