Read the given information and answer the question that follows.

The following table gives the percentage of marks obtained by seven students in six different subjects in an examination. The number in the brackets give the maximum marks in each subject.

Student	Subject (Max. Marks)
	Maths (150)	Chemistry (130)	Physics (120)	Geography (100)	History (60)	Computer Science (40)
Ayush	90	50	90	60	70	80
Aman	100	80	80	40	80	70
Sajal	90	60	70	70	90	70
Rohit	80	65	80	80	60	60
Muskan	80	65	85	95	50	90
Tanvi	70	75	65	85	40	60
Tarun	65	35	50	77	80	80

If someone secured all the highest scores obtained by any student in the six subjects as given in the table above, what would be the exact overall percentage score obtained by that student?

To find the overall percentage score obtained by a student who secured the highest score in each of the six subjects, we first need to determine the maximum marks and the highest marks obtained in each subject.

Note that the values given in the table are percentages of marks obtained, not the marks themselves.

Let's calculate the highest marks obtained in each subject:

1. Maths (Maximum Marks = 150):
The highest percentage obtained in Maths is 100% (by Aman).
Highest marks in Maths = $100\%\text{of}150=150$

2. Chemistry (Maximum Marks = 130):
The highest percentage obtained in Chemistry is 80% (by Aman).
Highest marks in Chemistry = $80\%\text{of}130=\frac{80}{100}\times 130=104$

3. Physics (Maximum Marks = 120):
The highest percentage obtained in Physics is 90% (by Ayush).
Highest marks in Physics = $90\%\text{of}120=\frac{90}{100}\times 120=108$

4. Geography (Maximum Marks = 100):
The highest percentage obtained in Geography is 95% (by Muskan).
Highest marks in Geography = $95\%\text{of}100=95$

5. History (Maximum Marks = 60):
The highest percentage obtained in History is 90% (by Sajal).
Highest marks in History = $90\%\text{of}60=\frac{90}{100}\times 60=54$

6. Computer Science (Maximum Marks = 40):
The highest percentage obtained in Computer Science is 90% (by Muskan).
Highest marks in Computer Science = $90\%\text{of}40=\frac{90}{100}\times 40=36$

Now, let's find the total maximum marks and the total highest marks obtained across all six subjects:

Total Maximum Marks = $150+130+120+100+60+40=600$

Total Marks Obtained = $150+104+108+95+54+36=547$

Finally, we calculate the overall percentage score:

Overall Percentage = $\left(\frac{547}{600}\right)\times 100\%=\frac{547}{6}\%$

Converting this fraction into a mixed fraction:

$\frac{547}{6}=91\frac{1}{6}$

Thus, the exact overall percentage score is $91\frac{1}{6}\%$ (or 91*1/6 %).