Study the given information carefully and answer the questions given below.

Nine people A, B, C, D, E, F, G, H, and I were born in different years i.e., 1998, 2000, 2003, 2004, 2005, 2010, 2012, 2015, and 2017 on the same date i.e., 31st December but not necessarily in the same order. Their ages are calculated as of 31st December 2021.

B is two years younger than A. The sum of the ages of C and D is 35, and C is older than D. The ages of F, G, and I are all perfect squares, where I is the youngest of the three and F is the oldest of the three. E is older than H.

How many persons were born between B and H?

The correct option is More than four.

Step 1: Calculate the age of each person as of 31st December 2021.
We calculate each person's age by subtracting their birth year from 2021:

• Born in 1998 → Age = 2021 - 1998 = 23 years old
• Born in 2000 → Age = 2021 - 2000 = 21 years old
• Born in 2003 → Age = 2021 - 2003 = 18 years old
• Born in 2004 → Age = 2021 - 2004 = 17 years old
• Born in 2005 → Age = 2021 - 2005 = 16 years old
• Born in 2010 → Age = 2021 - 2010 = 11 years old
• Born in 2012 → Age = 2021 - 2012 = 9 years old
• Born in 2015 → Age = 2021 - 2015 = 6 years old
• Born in 2017 → Age = 2021 - 2017 = 4 years old

The available ages in 2021 are: 23, 21, 18, 17, 16, 11, 9, 6, 4.

Step 2: Determine the ages of F, G, and I using the perfect square condition.
Looking at the list of ages (23, 21, 18, 17, 16, 11, 9, 6, 4), the numbers that are perfect squares are 16, 9, and 4.
We are given that F, G, and I have ages that are perfect squares, where F is the oldest and I is the youngest:
• Age of F = 16 (Born in 2005)
• Age of G = 9 (Born in 2012)
• Age of I = 4 (Born in 2017)

Step 3: Determine the ages of C and D.
We are given that the sum of the ages of C and D is 35, and C is older than D.
Let us check pairs of remaining ages (23, 21, 18, 17, 11, 6) that sum up to 35:
$18+17=35$
Since C is older than D:
• Age of C = 18 (Born in 2003)
• Age of D = 17 (Born in 2004)

Step 4: Determine the ages of A and B.
We are given that B is two years younger than A.
Looking at the remaining ages (23, 21, 11, 6):
• 23 - 21 = 2
So, A must be 23 years old and B must be 21 years old.
• Age of A = 23 (Born in 1998)
• Age of B = 21 (Born in 2000)

Step 5: Determine the ages of E and H.
The remaining available ages are 11 and 6.
We are given that E is older than H:
• Age of E = 11 (Born in 2010)
• Age of H = 6 (Born in 2015)

Step 6: Summary of Birth Years in Chronological Order:
• 1998: A (Age 23)
• 2000: B (Age 21)
• 2003: C (Age 18)
• 2004: D (Age 17)
• 2005: F (Age 16)
• 2010: E (Age 11)
• 2012: G (Age 9)
• 2015: H (Age 6)
• 2017: I (Age 4)

Step 7: Find the number of persons born between B (2000) and H (2015).
The people born between 2000 and 2015 are:
C (2003), D (2004), F (2005), E (2010), and G (2012).
Total persons born between B and H = 5 persons.

Since 5 is greater than 4, the correct option is More than four.