Study the given passage carefully and answer the questions.

Six students A, B, C, D, E and F participated in a test of 200 marks. C scored 50% marks which are 25% higher than that of E. ratio of marks obtained by A, B and F is 12:8:9 respectively. D scored 62.5% more marks than E. E and B score equal marks.

If passing marks is 40% of maximum marks then marks scored by D are what percent more than the passing marks?

Correct Answer: The correct option is 62.5%.

Let's solve the problem step-by-step using the information given in the passage.

Step 1: Determine the total maximum marks and passing marks.

Maximum marks for the test = 200

Passing marks = 40% of Maximum marks

$\text{Passing marks}=\frac{40}{100}\times 200=80$

Step 2: Calculate the marks scored by C.

C scored 50% of the maximum marks.

$\text{Marks scored by C}=\frac{50}{100}\times 200=100$

Step 3: Calculate the marks scored by E.

C's marks (100) are 25% higher than E's marks. This means C's marks are 125% of E's marks.

$100=1.25\times \text{Marks scored by E}$

$\text{Marks scored by E}=\frac{100}{1.25}=80$

Step 4: Calculate the marks scored by D.

D scored 62.5% more marks than E.

$\text{Marks scored by D}=80+(62.5\%\text{ of }80)$

$62.5\%\text{ of }80=\frac{62.5}{100}\times 80=\frac{5}{8}\times 80=50$

$\text{Marks scored by D}=80+50=130$

Step 5: Calculate by what percent D's marks are more than the passing marks.

Marks scored by D = 130

Passing marks = 80

$\text{Difference}=130-80=50$

$\text{Percentage more}=\left(\frac{50}{80}\right)\times 100=\frac{5}{8}\times 100=62.5\%$

Thus, the marks scored by D are 62.5% more than the passing marks.