Study the pie chart given below and answer the following questions. Pie charts shows the percentage distribution of total students in five different schools (A, B, C, D and E) and percentage distribution of total boys in these five schools in year 2019.

Total girls from school B and D together are what percent total students from school C and D together?

The correct answer is 24.1%.

From the pie charts given in the image, we have the following data:

• Total number of students in all five schools = 5000
• Total number of boys in all five schools = 2800

Step 1: Calculate total students in schools B, C, and D

• Total students in School B = 15% of 5000

$\text{Total students in B}=\frac{15}{100}\×5000=750$

• Total students in School C = 28% of 5000

$\text{Total students in C}=\frac{28}{100}\×5000=1400$

• Total students in School D = 12% of 5000

$\text{Total students in D}=\frac{12}{100}\×5000=600$

• Total students from School C and D together:

$\text{Total students (C + D)}=1400+600=2000$

Step 2: Calculate the number of boys and girls in school B and D

• Total boys in School B = 15% of 2800

$\text{Boys in B}=\frac{15}{100}\×2800=420$

• Girls in School B = Total students in B - Boys in B

$\text{Girls in B}=750-420=330$

• Total boys in School D = 16% of 2800

$\text{Boys in D}=\frac{16}{100}\×2800=448$

• Girls in School D = Total students in D - Boys in D

$\text{Girls in D}=600-448=152$

• Total girls from school B and D together:

$\text{Total girls (B + D)}=330+152=482$

Step 3: Calculate the required percentage

We need to find what percent total girls from school B and D together are of total students from school C and D together.

$\text{Required Percentage}=\left(\frac{\text{Total girls from B and D}}{\text{Total students from C and D}}\right)\×100$

$\text{Required Percentage}=\left(\frac{482}{2000}\right)\×100=\frac{482}{20}=24.1\%$

Hence, total girls from school B and D together are 24.1% of total students from school C and D together.