Study the pie chart given below and answer the following questions. Pie charts shows the percentage distribution of total students in five different schools (A, B, C, D and E) and percentage distribution of total boys in these five schools in year 2019.

If in 2020, the number of girls in school B increased by 20% while number of boys are decreased by 14$\frac{2}{7}$% over the previous year . Total students in school B in year 2020 are what percent more or less than the total students in school D in year 2019?

The correct option is 26%.

Analysis of the Data from the Image:

From the given pie charts representing the year 2019:
1. Total students across all 5 schools = 5000
- School B percentage of total students = 15%
- School D percentage of total students = 12%
2. Total boys across all 5 schools = 2800
- School B percentage of total boys = 15%

Step 1: Calculate the values for School B and School D in 2019

Total students in School B in 2019:

$\text{Total Students in B (2019)}=15\%\text{of}5000=\frac{15}{100}\times 5000=750$

Total boys in School B in 2019:

$\text{Total Boys in B (2019)}=15\%\text{of}2800=\frac{15}{100}\times 2800=420$

Total girls in School B in 2019:

$\text{Total Girls in B (2019)}=750-420=330$

Total students in School D in 2019:

$\text{Total Students in D (2019)}=12\%\text{of}5000=\frac{12}{100}\times 5000=600$

Step 2: Calculate the values for School B in 2020

In 2020, the number of girls in school B increased by 20% over the previous year:

$\text{Girls in B (2020)}=330\times \left(1+\frac{20}{100}\right)=330\times 1.2=396$

The number of boys in school B decreased by 14$\frac{2}{7}$% over the previous year:
Note that 14$\frac{2}{7}$% = $\frac{100}{7}$% = $\frac{1}{7}$.

$\text{Boys in B (2020)}=420\times \left(1-\frac{1}{7}\right)=420\times \frac{6}{7}=360$

Total students in School B in 2020:

$\text{Total Students in B (2020)}=396+360=756$

Step 3: Percentage comparison with School D in 2019

We need to find how much percent the total students in school B in 2020 (756) are more than the total students in school D in 2019 (600):

$\text{Difference}=756-600=156$

Percentage more:

$\text{Required Percentage}=\left(\frac{156}{600}\right)\times 100=\frac{156}{6}=26\%$

Therefore, total students in school B in 2020 are 26% more than total students in school D in 2019.