Question Details

Table given below shows total number of people (Adult + Children) visited four different parks in a week. The table also shows total number of males and ratio of male to female in adult people. Read the data carefully and answer the questions.

ParksTotal people (Adult + children)Total number of malesThe ratio of total number of males to that of females in adult people
A220080P----
B144040P----
C120045P9 : 4
D48015P5 : 3

Note: (i) Adult = Male + female
(ii) Total number of adult males visited all four parks in the week = 2700

Find the difference between total male visited parks C & D together and total female visited in same parks.

Options

A

525

B

435

C

565

D

465

E

555

Show Answer

Correct Answer :

Option D

465

Solution :

The correct option is 465.

Step 1: Determine the value of P
According to Note (ii), the total number of adult males who visited all four parks is 2700.
From the table, the total number of males for parks A, B, C, and D are given as 80P, 40P, 45P, and 15P respectively.
Summing these values:

80 P + 40 P + 45 P + 15 P = 2700

180 P = 2700

P = 2700 180 = 15

Step 2: Calculate total males visited in parks C and D
Using P=15:

Total males in park C = 45 × 15 = 675

Total males in park D = 15 × 15 = 225

Total males in C & D together = 675 + 225 = 900

Step 3: Calculate total females visited in parks C and D
Note (i) states that Adult = Male + Female, which means Male : Female ratio gives the number of adult females.

For park C:
The ratio of males to females is 9 : 4.
Since Total males in park C = 675:

Females in C = 675 × 4 9 = 75 × 4 = 300

For park D:
The ratio of males to females is 5 : 3.
Since Total males in park D = 225:

Females in D = 225 × 3 5 = 45 × 3 = 135

Total females in C & D together = 300 + 135 = 435

Step 4: Find the required difference
Difference = (Total males in C & D) - (Total females in C & D)

Difference = 900 - 435 = 465

Hence, the difference between total males visited parks C & D together and total females visited in the same parks is 465.

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