Tarun is twice as good as Tripti in doing a work. Together, they can complete the work in 16 days. In how many days can Tripti alone complete the same work?

To find the number of days Tripti alone takes to complete the work, we can use the concept of work efficiency.

Let Tripti's daily work efficiency be $x$ units of work per day.
Since Tarun is twice as good as Tripti, Tarun's efficiency is twice that of Tripti's.
Therefore, Tarun's daily work efficiency = $2x$ units of work per day.

When they work together, their combined daily efficiency is the sum of their individual efficiencies:
Combined efficiency = $x+2x=3x$ units of work per day.

We are given that together they can complete the work in 16 days.
The total work is equal to the daily efficiency multiplied by the time taken to complete it:
Total work = $3x\times 16=48x$ units.

Now, we want to find the number of days Tripti alone would take to complete this total work of $48x$ units.
Time taken by Tripti = Total work / Tripti's efficiency
Time taken by Tripti = $\frac{48x}{x}=48$ days.

Thus, Tripti alone can complete the work in 48 days.