Question Details

The approximate distance between the capital of Madhya Pradesh (Bhopal) and the capital of Maharashtra (Mumbai) is 756 km. If a train covers this distance in nearly 14 hours, the average speed of the train in metre per second is

Options

A

15 m/s

B

30 m/s

C

54 m/s

D

900 m/s

Show Answer

Correct Answer :

Option A

15 m/s

15 m/s

Solution :

The correct option is 15 m/s.

To find the average speed of the train in meters per second (m/s), we can follow these steps:

Step 1: Identify the given values

Distance, d=756 km

Time taken, t=14 hours

Step 2: Calculate the average speed in kilometers per hour (km/h)

The formula for average speed is:

Average Speed=DistanceTime

Substituting the given values:

Average Speed=75614=54 km/h

Step 3: Convert the speed from km/h to m/s

To convert speed from kilometers per hour (km/h) to meters per second (m/s), we multiply the speed value by the conversion factor:

1000 m3600 s=518

Applying this conversion factor:

Speed in m/s=54×518

Speed in m/s=3×5=15 m/s

Therefore, the average speed of the train is 15 m/s.

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