The bar shows the total number of students in four schools and it also shows the difference between boys and girls in these schools.

Total girls in A and B together is what percentage of more than that of girls in C.

First, we analyze the bar chart to find the number of girls in schools A, B, and C.
The chart provides the following values for each school:
• Blue bar represents the sum of boys and girls: Boys + Girls
• Orange bar represents the difference: Boys - Girls

To find the number of girls in any school, we can use the formula:

$\text{Girls}=\frac{(\text{Boys}+\text{Girls})-(\text{Boys}-\text{Girls})}{2}$

Let's calculate the number of girls for schools A, B, and C:

1. School A:
• Boys + Girls = 72 (from the blue bar for A)
• Boys - Girls = 48 (from the orange bar for A)

${\text{Girls}}_{\text{A}}=\frac{72-48}{2}=\frac{24}{2}=12$

2. School B:
• Boys + Girls = 60 (from the blue bar for B)
• Boys - Girls = 28 (from the orange bar for B)

${\text{Girls}}_{\text{B}}=\frac{60-28}{2}=\frac{32}{2}=16$

3. School C:
• Boys + Girls = 48 (from the blue bar for C)
• Boys - Girls = 12 (from the orange bar for C)

${\text{Girls}}_{\text{C}}=\frac{48-12}{2}=\frac{36}{2}=18$

Next, we calculate the total number of girls in schools A and B together:

$\text{Total girls in A and B}=12+16=28$

Now, we find how many more girls are in schools A and B combined than in school C (which has 18 girls):
Difference = 28 - 18 = 10

We calculate the percentage by which the combined girls of A and B exceeds the girls of C:

$\text{Percentage more}=\frac{10}{18}\times 100=\frac{5}{9}\times 100\approx \mathrm{55.55\%}$

Therefore, the total girls in A and B together is 55.55% more than the girls in C.