The bar shows the total number of students in four schools and it also shows the difference between boys and girls in these schools.

In school E, the ratio of boys and girls be 7: 9 and boys in E is 50% more than girls in A and B together. Find the girls in E.

The correct answer is 54.

Step-by-step explanation:

From the given bar graph:
- The blue bar represents the total number of students, i.e., (Boys + Girls).
- The orange bar represents the difference between boys and girls, i.e., (Boys - Girls).

Step 1: Find the number of girls in School A and School B.

For School A:
Boys + Girls = 72
Boys - Girls = 48

Subtracting the two equations gives:

$2\times \text{Girls in A}=72-48=24$

$\text{Girls in A}=\frac{24}{2}=12$

For School B:
Boys + Girls = 60
Boys - Girls = 28

Subtracting the two equations gives:

$2\times \text{Girls in B}=60-28=32$

$\text{Girls in B}=\frac{32}{2}=16$

Step 2: Find the total number of girls in A and B together.

$\text{Girls in A and B together}=12+16=28$

Step 3: Calculate the number of boys in School E.

The boys in E is 50% more than the total girls in A and B together:

$\text{Boys in E}=28+(50\%\text{of}28)$

$\text{Boys in E}=28+14=42$

Step 4: Calculate the number of girls in School E.

Given that the ratio of boys to girls in school E is 7 : 9:

$\frac{\text{Boys in E}}{\text{Girls in E}}=\frac{7}{9}$

$\frac{42}{\text{Girls in E}}=\frac{7}{9}$

$\text{Girls in E}=\frac{42\times 9}{7}=6\times 9=54$

Thus, the number of girls in school E is 54.