The compound(s) which react(s) with NH₃ to given boron nitride (BN) is (are)

The correct options are B, B₂H₆, and B₂O₃.

Boron nitride $\left(\text{BN}\right)$ can be prepared by reacting several boron-containing compounds with ammonia $\left({\text{NH}}_3\right)$ under suitable high-temperature reaction conditions:

1. Reaction with Elemental Boron (B):

Elemental boron reacts directly with ammonia gas at high temperatures (red heat) to yield boron nitride and hydrogen gas:

$2\text{B}+2{\text{NH}}_3\to 2\text{BN}+3{\text{H}}_2$

2. Reaction with Diborane (B₂H₆):

Diborane reacts with excess ammonia at high temperatures to produce boron nitride along with hydrogen gas:

${\text{B}}_2{\text{H}}_6+2{\text{NH}}_3\to 2\text{BN}+6{\text{H}}_2$

3. Reaction with Boron Trioxide (B₂O₃):

Boron trioxide reacts with ammonia at elevated temperatures to form boron nitride and water vapor:

${\text{B}}_2{\text{O}}_3+2{\text{NH}}_3\to 2\text{BN}+3{\text{H}}_2\text{O}$

Therefore, boron (B), diborane (B₂H₆), and boron trioxide (B₂O₃) all react with ammonia to produce boron nitride (BN).