The following Table-1 and Table-2

Show the breakup of 4170 vacant posts in six Banks A-F, and the percentage (%) breakup of the requirement of personnel in six different cadres in a Bank, namely, IT officers (ITO), Agricultural Field Officers (AFO), Law Officers (LO), Finance Executives (FE), Technical Officers (TO) and Probationary Officers (PO), respectively. Assume that these percentages are the same for all the six Banks. Based on the data in the tables, answer the questions.

Tables 1: Bank-wise Vacant Posts

Bank	Bank Number of Vacant Posts
A	800
B	940
C	600
D	820
E	450
F	560

Table 2:

Cadre in a Bank	Breakup (%)
ITO	11%
AFO	35%
LO	10%
FE	26%
TO	8%
PO	10

The ratio of recruitment of AFOS in C and E taken together with that of D and F taken together is

The correct answer is 35:46.

To find the ratio of recruitment of Agricultural Field Officers (AFOs) in Banks C and E taken together to that of Banks D and F taken together, we follow these steps:

Step 1: Identify the percentage breakup of AFOs in any bank
According to Table 2, the percentage breakup for AFOs is 35% across all banks.

Step 2: Retrieve the number of vacant posts from Table 1
From Table 1, the number of vacant posts for the required banks are:
- Bank C = 600
- Bank E = 450
- Bank D = 820
- Bank F = 560

Step 3: Calculate the total vacant posts for each combined group
- For C and E taken together:
$$600+450=1050$$
- For D and F taken together:
$$820+560=1380$$

Step 4: Set up the ratio of AFO recruitment
Since the percentage requirement of AFOs (35%) is constant for all banks, the ratio of AFOs recruited in the two groups is directly proportional to the total vacant posts in those groups:
$$\text{Ratio}=\frac{35\%\text{of}1050}{35\%\text{of}1380}=\frac{1050}{1380}$$

Step 5: Simplify the ratio
Dividing both the numerator and the denominator by 10:
$$\frac{105}{138}$$
Next, dividing both terms by their greatest common divisor, which is 3:
$$\frac{105/3}{138/3}=\frac{35}{46}$$
Therefore, the ratio of recruitment is 35:46.