The following Table-1 and Table-2

Show the breakup of 4170 vacant posts in six Banks A-F, and the percentage (%) breakup of the requirement of personnel in six different cadres in a Bank, namely, IT officers (ITO), Agricultural Field Officers (AFO), Law Officers (LO), Finance Executives (FE), Technical Officers (TO) and Probationary Officers (PO), respectively. Assume that these percentages are the same for all the six Banks. Based on the data in the tables, answer the questions.

Tables 1: Bank-wise Vacant Posts

Bank	Bank Number of Vacant Posts
A	800
B	940
C	600
D	820
E	450
F	560

Table 2:

Cadre in a Bank	Breakup (%)
ITO	11%
AFO	35%
LO	10%
FE	26%
TO	8%
PO	10

By what percent is the number of recruitments of LOS more/less in C, E and F taken together than in A, B and D taken together?

The correct option is Less By 37.11%.

Step-by-Step Explanation:

1. Understand the given data:
From Table 1, we can find the number of vacant posts in each bank:
Bank A = 800 vacant posts
Bank B = 940 vacant posts
Bank C = 600 vacant posts
Bank D = 820 vacant posts
Bank E = 450 vacant posts
Bank F = 560 vacant posts

From Table 2, the percentage breakup of Law Officers (LO) is 10% of the total vacant posts, which remains the same for all banks.

2. Calculate the total vacant posts in banks C, E, and F taken together:
Total vacant posts in C, E, and F = Vacant posts in C + Vacant posts in E + Vacant posts in F
Total (C + E + F) = 600 + 450 + 560 = 1610

Since the percentage of Law Officers (LO) is 10% for all banks, the total LO recruitments in C, E, and F is:

$$\text{LO in C, E, F}=10\%\text{of}1610=\frac{10}{100}\times 1610=161$$

3. Calculate the total vacant posts in banks A, B, and D taken together:
Total vacant posts in A, B, and D = Vacant posts in A + Vacant posts in B + Vacant posts in D
Total (A + B + D) = 800 + 940 + 820 = 2560

Similarly, the total LO recruitments in A, B, and D is:

$$\text{LO in A, B, D}=10\%\text{of}2560=\frac{10}{100}\times 2560=256$$

4. Compare the recruitments:
We want to find by what percent the number of LO recruitments in C, E, and F (161) is more or less than that in A, B, and D (256).
Since 161 is less than 256, it is a percentage decrease (less by):

$$\text{Difference}=256-161=95$$

Now, calculate the percentage relative to the total in A, B, and D:

$$\text{Percentage Less}=\left(\frac{\text{Difference}}{\text{LO in A, B, D}}\right)\times 100\%$$

$$\text{Percentage Less}=\left(\frac{95}{256}\right)\times 100\%\approx 0.37109\times 100\%\approx 37.11\%$$

Thus, the number of recruitments of LOs in C, E, and F taken together is Less By 37.11% than in A, B, and D taken together.