The information given about number of project handle by two companies (A and B) in three different years (2015, 2016 and 2017). Read the information carefully and answer the questions given below.

In 2015, Total projects handle by A are 1.5 times of B.
In 2016, Total project handle by B is 9 more than that of in 2015 and A handle 20 projects.
In 2017, total project handle by A is 25% more than that of by B in 2015 and B handle 30 projects.
Total projects handle by A in all three years is 42.

Find the projects handle by B in 2017 is how much more or less than the projects handle by A in 2016.

To find the difference between the number of projects handled by B in 2017 and A in 2016, we need to systematically determine the number of projects handled by each company (A and B) in each of the given years (2015, 2016, and 2017).

Let's define variables for the number of projects:
Let the number of projects handled by company B in 2015 be $x$.
According to the given information, in 2015, the total projects handled by company A are 1.5 times those of company B.
Therefore, the number of projects handled by A in 2015 = $1.5x$.

Now, let's look at the data for 2016:
- The total projects handled by B in 2016 is 9 more than that of B in 2015:
Projects handled by B in 2016 = $x+9$.
- The total projects handled by A in 2016 is explicitly given:
Projects handled by A in 2016 = 20.

Next, let's look at the data for 2017:
- The total projects handled by A in 2017 is 25% more than that by B in 2015:
Projects handled by A in 2017 = $x+0.25x=1.25x$.
- The total projects handled by B in 2017 is explicitly given:
Projects handled by B in 2017 = 30.

We are given that the total projects handled by A in all three years (2015, 2016, and 2017) is 42.
Using this information, we can write the equation:
$\left(\text{Projects by A in 2015}\right)+\left(\text{Projects by A in 2016}\right)+\left(\text{Projects by A in 2017}\right)=42$
Substituting the values we expressed in terms of $x$:
$1.5x+20+1.25x=42$

Now, let's solve for $x$:
Combine the like terms containing $x$:
$2.75x+20=42$
Subtract 20 from both sides:
$2.75x=22$
Divide by 2.75 (which is equivalent to 11/4):
$x=\frac{22}{2.75}=\frac{22}{\frac{11}{4}}=22\times \frac{4}{11}=2\times 4=8$

So, the number of projects handled by B in 2015 ($x$) is 8.

The question asks: "Find the projects handled by B in 2017 is how much more or less than the projects handled by A in 2016."
From the given data and our calculations:
- Projects handled by B in 2017 = 30.
- Projects handled by A in 2016 = 20.
Comparing the two values:
$30-20=10$

Thus, the projects handled by B in 2017 is 10 more than the projects handled by A in 2016.
The correct answer is 10.