Question Details

The number of real-valued solutions of the equation 2x+2-x=2-(x-2)2 is

Options

A

infinite

B

1

C

0

D

2

Show Answer

Correct Answer :

Option C

0

Solution :

Given equation:
x2-x2-x2-2=x2-22

Simplifying the left-hand side:
-x2-2=x2-22

-x2+2=x2-22

For any real number x:
x20

Therefore, the term on the left side is always strictly negative:
-x2+2-2<0

However, the term on the right side is a perfect square, which must always be non-negative:
x2-220

Since a strictly negative value can never equal a non-negative value for any real x, there are no real solutions to this equation. Thus, the number of real-valued solutions is 0.

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