The pie given below shows the total population in five cities (A, B, C, D, E).

The population of cities D and E is what percentage more/less than the total population of A and C

The correct option is 58.46%.


From the given pie chart showing the population distribution across five cities A, B, C, D, and E:

• Total Population = 1200
• City A = $(2p+5)\%$
• City B = 8%
• City C = $p\%$
• City D = 15%
• City E = 12%

Step 1: Determine the value of $p$

Since the total percentage in a pie chart must equal 100%:

$(2p+5)+8+p+15+12=100$

$3p+40=100$

$3p=60$

$p=20$

Step 2: Calculate the percentage share of each city

• City A = $2\left(20\right)+5=45\%$
• City C = $20\%$
• City D = $15\%$
• City E = $12\%$

Step 3: Calculate combined percentages for (D + E) and (A + C)

$\text{Percentage share of D and E}=15\%+12\%=27\%$

$\text{Percentage share of A and C}=45\%+20\%=65\%$

Step 4: Find the required percentage less

Difference in percentages:

$\text{Difference}=65\%-27\%=38\%$

Percentage by which population of D and E is less than that of A and C:

$\text{Percentage Less}=\left(\frac{38}{65}\right)\times 100$

$=\frac{3800}{65}=\frac{760}{13}\approx 58.46\%$

Therefore, the population of cities D and E is 58.46% less than the total population of cities A and C.