The pie given below shows the total population in five cities (A, B, C, D, E).

Out of the total population of all the cities 35% are females and 55% of the total population of city D are females. Total females in all the cities except D is how many more/ less than total population of A.

Correct Answer: 219

Based on the provided pie chart, we have the following data:

Total Population of all five cities = 1200
Percentage distribution of population across cities:
City A = (2p + 5)%
City B = 8%
City C = p%
City D = 15%
City E = 12%

Step 1: Find the value of p.
The sum of the percentage shares of all five cities in a pie chart must equal 100%:
$(2p+5)+8+p+15+12=100$
$3p+40=100$
$3p=60$
$p=20$

Step 2: Calculate the total population of City A.
Percentage share of City A = $(2p+5)\%=(2\times 20+5)\%=45\%$
Total population of City A = $\frac{45}{100}\times 1200=540$

Step 3: Calculate total females in all cities.
Given that 35% of the total population of all cities are females:
Total females in all cities = $35100\times 1200=420$

Step 4: Calculate females in City D.
Population of City D = $\frac{15}{100}\times 1200=180$
Given that 55% of the total population of City D are females:
Females in City D = $\frac{55}{100}\times 180=99$

Step 5: Calculate total females in all cities except City D.
Females in all cities except D = Total females in all cities - Females in City D
$420-99=321$

Step 6: Calculate the required difference.
Difference between total population of City A and total females in all cities except D:
$540-321=219$
Therefore, the total females in all cities except D is 219 less than the total population of City A.